3.4.20 \(\int \frac {1}{x^4 (d+e x) (a d e+(c d^2+a e^2) x+c d e x^2)^{3/2}} \, dx\)

Optimal. Leaf size=664 \[ \frac {2 \left (-9 a^3 e^6+c d e x \left (-9 a^2 e^4+14 a c d^2 e^2+3 c^2 d^4\right )+13 a^2 c d^2 e^4+a c^2 d^4 e^2+3 c^3 d^6\right )}{3 a d^2 e x^3 \left (c d^2-a e^2\right )^3 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}-\frac {\left (-21 a^3 e^6+33 a^2 c d^2 e^4-3 a c^2 d^4 e^2+7 c^3 d^6\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{3 a^2 d^3 e^2 x^3 \left (c d^2-a e^2\right )^3}+\frac {5 \left (21 a^3 e^6+21 a^2 c d^2 e^4+15 a c^2 d^4 e^2+7 c^3 d^6\right ) \tanh ^{-1}\left (\frac {x \left (a e^2+c d^2\right )+2 a d e}{2 \sqrt {a} \sqrt {d} \sqrt {e} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\right )}{16 a^{9/2} d^{11/2} e^{9/2}}+\frac {\left (-105 a^4 e^8+168 a^3 c d^2 e^6-18 a^2 c^2 d^4 e^4-16 a c^3 d^6 e^2+35 c^4 d^8\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{12 a^3 d^4 e^3 x^2 \left (c d^2-a e^2\right )^3}-\frac {\left (-315 a^5 e^{10}+525 a^4 c d^2 e^8-78 a^3 c^2 d^4 e^6-54 a^2 c^3 d^6 e^4-55 a c^4 d^8 e^2+105 c^5 d^{10}\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{24 a^4 d^5 e^4 x \left (c d^2-a e^2\right )^3}-\frac {2 e (a e+c d x)}{3 d x^3 \left (c d^2-a e^2\right ) \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}} \]

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Rubi [A]  time = 1.17, antiderivative size = 664, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 40, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {851, 822, 834, 806, 724, 206} \begin {gather*} -\frac {\left (33 a^2 c d^2 e^4-21 a^3 e^6-3 a c^2 d^4 e^2+7 c^3 d^6\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{3 a^2 d^3 e^2 x^3 \left (c d^2-a e^2\right )^3}-\frac {\left (-54 a^2 c^3 d^6 e^4-78 a^3 c^2 d^4 e^6+525 a^4 c d^2 e^8-315 a^5 e^{10}-55 a c^4 d^8 e^2+105 c^5 d^{10}\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{24 a^4 d^5 e^4 x \left (c d^2-a e^2\right )^3}+\frac {\left (-18 a^2 c^2 d^4 e^4+168 a^3 c d^2 e^6-105 a^4 e^8-16 a c^3 d^6 e^2+35 c^4 d^8\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{12 a^3 d^4 e^3 x^2 \left (c d^2-a e^2\right )^3}+\frac {2 \left (c d e x \left (-9 a^2 e^4+14 a c d^2 e^2+3 c^2 d^4\right )+13 a^2 c d^2 e^4-9 a^3 e^6+a c^2 d^4 e^2+3 c^3 d^6\right )}{3 a d^2 e x^3 \left (c d^2-a e^2\right )^3 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}+\frac {5 \left (21 a^2 c d^2 e^4+21 a^3 e^6+15 a c^2 d^4 e^2+7 c^3 d^6\right ) \tanh ^{-1}\left (\frac {x \left (a e^2+c d^2\right )+2 a d e}{2 \sqrt {a} \sqrt {d} \sqrt {e} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\right )}{16 a^{9/2} d^{11/2} e^{9/2}}-\frac {2 e (a e+c d x)}{3 d x^3 \left (c d^2-a e^2\right ) \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x^4*(d + e*x)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)),x]

[Out]

(-2*e*(a*e + c*d*x))/(3*d*(c*d^2 - a*e^2)*x^3*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)) + (2*(3*c^3*d^6 +
a*c^2*d^4*e^2 + 13*a^2*c*d^2*e^4 - 9*a^3*e^6 + c*d*e*(3*c^2*d^4 + 14*a*c*d^2*e^2 - 9*a^2*e^4)*x))/(3*a*d^2*e*
(c*d^2 - a*e^2)^3*x^3*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2]) - ((7*c^3*d^6 - 3*a*c^2*d^4*e^2 + 33*a^2*c*
d^2*e^4 - 21*a^3*e^6)*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2])/(3*a^2*d^3*e^2*(c*d^2 - a*e^2)^3*x^3) + ((3
5*c^4*d^8 - 16*a*c^3*d^6*e^2 - 18*a^2*c^2*d^4*e^4 + 168*a^3*c*d^2*e^6 - 105*a^4*e^8)*Sqrt[a*d*e + (c*d^2 + a*e
^2)*x + c*d*e*x^2])/(12*a^3*d^4*e^3*(c*d^2 - a*e^2)^3*x^2) - ((105*c^5*d^10 - 55*a*c^4*d^8*e^2 - 54*a^2*c^3*d^
6*e^4 - 78*a^3*c^2*d^4*e^6 + 525*a^4*c*d^2*e^8 - 315*a^5*e^10)*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2])/(2
4*a^4*d^5*e^4*(c*d^2 - a*e^2)^3*x) + (5*(7*c^3*d^6 + 15*a*c^2*d^4*e^2 + 21*a^2*c*d^2*e^4 + 21*a^3*e^6)*ArcTanh
[(2*a*d*e + (c*d^2 + a*e^2)*x)/(2*Sqrt[a]*Sqrt[d]*Sqrt[e]*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2])])/(16*a
^(9/2)*d^(11/2)*e^(9/2))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 724

Int[1/(((d_.) + (e_.)*(x_))*Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]), x_Symbol] :> Dist[-2, Subst[Int[1/(4*c*d
^2 - 4*b*d*e + 4*a*e^2 - x^2), x], x, (2*a*e - b*d - (2*c*d - b*e)*x)/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a,
b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[2*c*d - b*e, 0]

Rule 806

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> -Si
mp[((e*f - d*g)*(d + e*x)^(m + 1)*(a + b*x + c*x^2)^(p + 1))/(2*(p + 1)*(c*d^2 - b*d*e + a*e^2)), x] - Dist[(b
*(e*f + d*g) - 2*(c*d*f + a*e*g))/(2*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x],
x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && EqQ[Sim
plify[m + 2*p + 3], 0]

Rule 822

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp
[((d + e*x)^(m + 1)*(f*(b*c*d - b^2*e + 2*a*c*e) - a*g*(2*c*d - b*e) + c*(f*(2*c*d - b*e) - g*(b*d - 2*a*e))*x
)*(a + b*x + c*x^2)^(p + 1))/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^2)), x] + Dist[1/((p + 1)*(b^2 - 4*a*
c)*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^m*(a + b*x + c*x^2)^(p + 1)*Simp[f*(b*c*d*e*(2*p - m + 2) + b^2*e^2
*(p + m + 2) - 2*c^2*d^2*(2*p + 3) - 2*a*c*e^2*(m + 2*p + 3)) - g*(a*e*(b*e - 2*c*d*m + b*e*m) - b*d*(3*c*d -
b*e + 2*c*d*p - b*e*p)) + c*e*(g*(b*d - 2*a*e) - f*(2*c*d - b*e))*(m + 2*p + 4)*x, x], x], x] /; FreeQ[{a, b,
c, d, e, f, g, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && LtQ[p, -1] && (IntegerQ[m] ||
IntegerQ[p] || IntegersQ[2*m, 2*p])

Rule 834

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Sim
p[((e*f - d*g)*(d + e*x)^(m + 1)*(a + b*x + c*x^2)^(p + 1))/((m + 1)*(c*d^2 - b*d*e + a*e^2)), x] + Dist[1/((m
+ 1)*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p*Simp[(c*d*f - f*b*e + a*e*g)*(m + 1)
+ b*(d*g - e*f)*(p + 1) - c*(e*f - d*g)*(m + 2*p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] &&
NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && LtQ[m, -1] && (IntegerQ[m] || IntegerQ[p] || IntegersQ
[2*m, 2*p])

Rule 851

Int[((d_) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :>
Int[((f + g*x)^n*(a + b*x + c*x^2)^(m + p))/(a/d + (c*x)/e)^m, x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] &&
NeQ[e*f - d*g, 0] && NeQ[b^2 - 4*a*c, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[p] && ILtQ[m, 0] && In
tegerQ[n] && (LtQ[n, 0] || GtQ[p, 0])

Rubi steps

\begin {align*} \int \frac {1}{x^4 (d+e x) \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx &=\int \frac {a e+c d x}{x^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}} \, dx\\ &=-\frac {2 e (a e+c d x)}{3 d \left (c d^2-a e^2\right ) x^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {2 \int \frac {-\frac {3}{2} a e \left (c d^2-3 a e^2\right ) \left (c d^2-a e^2\right )+5 a c d e^2 \left (c d^2-a e^2\right ) x}{x^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx}{3 a d e \left (c d^2-a e^2\right )^2}\\ &=-\frac {2 e (a e+c d x)}{3 d \left (c d^2-a e^2\right ) x^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {2 \left (3 c^3 d^6+a c^2 d^4 e^2+13 a^2 c d^2 e^4-9 a^3 e^6+c d e \left (3 c^2 d^4+14 a c d^2 e^2-9 a^2 e^4\right ) x\right )}{3 a d^2 e \left (c d^2-a e^2\right )^3 x^3 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {4 \int \frac {\frac {3}{4} a e \left (c d^2-a e^2\right ) \left (7 c^3 d^6-3 a c^2 d^4 e^2+33 a^2 c d^2 e^4-21 a^3 e^6\right )+\frac {3}{2} a c d e^2 \left (c d^2-a e^2\right ) \left (3 c^2 d^4+14 a c d^2 e^2-9 a^2 e^4\right ) x}{x^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{3 a^2 d^2 e^2 \left (c d^2-a e^2\right )^4}\\ &=-\frac {2 e (a e+c d x)}{3 d \left (c d^2-a e^2\right ) x^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {2 \left (3 c^3 d^6+a c^2 d^4 e^2+13 a^2 c d^2 e^4-9 a^3 e^6+c d e \left (3 c^2 d^4+14 a c d^2 e^2-9 a^2 e^4\right ) x\right )}{3 a d^2 e \left (c d^2-a e^2\right )^3 x^3 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (7 c^3 d^6-3 a c^2 d^4 e^2+33 a^2 c d^2 e^4-21 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 a^2 d^3 e^2 \left (c d^2-a e^2\right )^3 x^3}-\frac {4 \int \frac {\frac {3}{8} a e \left (c d^2-a e^2\right ) \left (35 c^4 d^8-16 a c^3 d^6 e^2-18 a^2 c^2 d^4 e^4+168 a^3 c d^2 e^6-105 a^4 e^8\right )+\frac {3}{2} a c d e^2 \left (c d^2-a e^2\right ) \left (7 c^3 d^6-3 a c^2 d^4 e^2+33 a^2 c d^2 e^4-21 a^3 e^6\right ) x}{x^3 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{9 a^3 d^3 e^3 \left (c d^2-a e^2\right )^4}\\ &=-\frac {2 e (a e+c d x)}{3 d \left (c d^2-a e^2\right ) x^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {2 \left (3 c^3 d^6+a c^2 d^4 e^2+13 a^2 c d^2 e^4-9 a^3 e^6+c d e \left (3 c^2 d^4+14 a c d^2 e^2-9 a^2 e^4\right ) x\right )}{3 a d^2 e \left (c d^2-a e^2\right )^3 x^3 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (7 c^3 d^6-3 a c^2 d^4 e^2+33 a^2 c d^2 e^4-21 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 a^2 d^3 e^2 \left (c d^2-a e^2\right )^3 x^3}+\frac {\left (35 c^4 d^8-16 a c^3 d^6 e^2-18 a^2 c^2 d^4 e^4+168 a^3 c d^2 e^6-105 a^4 e^8\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{12 a^3 d^4 e^3 \left (c d^2-a e^2\right )^3 x^2}+\frac {2 \int \frac {\frac {3}{16} a e \left (c d^2-a e^2\right ) \left (105 c^5 d^{10}-55 a c^4 d^8 e^2-54 a^2 c^3 d^6 e^4-78 a^3 c^2 d^4 e^6+525 a^4 c d^2 e^8-315 a^5 e^{10}\right )+\frac {3}{8} a c d e^2 \left (c d^2-a e^2\right ) \left (35 c^4 d^8-16 a c^3 d^6 e^2-18 a^2 c^2 d^4 e^4+168 a^3 c d^2 e^6-105 a^4 e^8\right ) x}{x^2 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{9 a^4 d^4 e^4 \left (c d^2-a e^2\right )^4}\\ &=-\frac {2 e (a e+c d x)}{3 d \left (c d^2-a e^2\right ) x^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {2 \left (3 c^3 d^6+a c^2 d^4 e^2+13 a^2 c d^2 e^4-9 a^3 e^6+c d e \left (3 c^2 d^4+14 a c d^2 e^2-9 a^2 e^4\right ) x\right )}{3 a d^2 e \left (c d^2-a e^2\right )^3 x^3 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (7 c^3 d^6-3 a c^2 d^4 e^2+33 a^2 c d^2 e^4-21 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 a^2 d^3 e^2 \left (c d^2-a e^2\right )^3 x^3}+\frac {\left (35 c^4 d^8-16 a c^3 d^6 e^2-18 a^2 c^2 d^4 e^4+168 a^3 c d^2 e^6-105 a^4 e^8\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{12 a^3 d^4 e^3 \left (c d^2-a e^2\right )^3 x^2}-\frac {\left (105 c^5 d^{10}-55 a c^4 d^8 e^2-54 a^2 c^3 d^6 e^4-78 a^3 c^2 d^4 e^6+525 a^4 c d^2 e^8-315 a^5 e^{10}\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{24 a^4 d^5 e^4 \left (c d^2-a e^2\right )^3 x}-\frac {\left (5 \left (7 c^3 d^6+15 a c^2 d^4 e^2+21 a^2 c d^2 e^4+21 a^3 e^6\right )\right ) \int \frac {1}{x \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{16 a^4 d^5 e^4}\\ &=-\frac {2 e (a e+c d x)}{3 d \left (c d^2-a e^2\right ) x^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {2 \left (3 c^3 d^6+a c^2 d^4 e^2+13 a^2 c d^2 e^4-9 a^3 e^6+c d e \left (3 c^2 d^4+14 a c d^2 e^2-9 a^2 e^4\right ) x\right )}{3 a d^2 e \left (c d^2-a e^2\right )^3 x^3 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (7 c^3 d^6-3 a c^2 d^4 e^2+33 a^2 c d^2 e^4-21 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 a^2 d^3 e^2 \left (c d^2-a e^2\right )^3 x^3}+\frac {\left (35 c^4 d^8-16 a c^3 d^6 e^2-18 a^2 c^2 d^4 e^4+168 a^3 c d^2 e^6-105 a^4 e^8\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{12 a^3 d^4 e^3 \left (c d^2-a e^2\right )^3 x^2}-\frac {\left (105 c^5 d^{10}-55 a c^4 d^8 e^2-54 a^2 c^3 d^6 e^4-78 a^3 c^2 d^4 e^6+525 a^4 c d^2 e^8-315 a^5 e^{10}\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{24 a^4 d^5 e^4 \left (c d^2-a e^2\right )^3 x}+\frac {\left (5 \left (7 c^3 d^6+15 a c^2 d^4 e^2+21 a^2 c d^2 e^4+21 a^3 e^6\right )\right ) \operatorname {Subst}\left (\int \frac {1}{4 a d e-x^2} \, dx,x,\frac {2 a d e-\left (-c d^2-a e^2\right ) x}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}\right )}{8 a^4 d^5 e^4}\\ &=-\frac {2 e (a e+c d x)}{3 d \left (c d^2-a e^2\right ) x^3 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {2 \left (3 c^3 d^6+a c^2 d^4 e^2+13 a^2 c d^2 e^4-9 a^3 e^6+c d e \left (3 c^2 d^4+14 a c d^2 e^2-9 a^2 e^4\right ) x\right )}{3 a d^2 e \left (c d^2-a e^2\right )^3 x^3 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (7 c^3 d^6-3 a c^2 d^4 e^2+33 a^2 c d^2 e^4-21 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 a^2 d^3 e^2 \left (c d^2-a e^2\right )^3 x^3}+\frac {\left (35 c^4 d^8-16 a c^3 d^6 e^2-18 a^2 c^2 d^4 e^4+168 a^3 c d^2 e^6-105 a^4 e^8\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{12 a^3 d^4 e^3 \left (c d^2-a e^2\right )^3 x^2}-\frac {\left (105 c^5 d^{10}-55 a c^4 d^8 e^2-54 a^2 c^3 d^6 e^4-78 a^3 c^2 d^4 e^6+525 a^4 c d^2 e^8-315 a^5 e^{10}\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{24 a^4 d^5 e^4 \left (c d^2-a e^2\right )^3 x}+\frac {5 \left (7 c^3 d^6+15 a c^2 d^4 e^2+21 a^2 c d^2 e^4+21 a^3 e^6\right ) \tanh ^{-1}\left (\frac {2 a d e+\left (c d^2+a e^2\right ) x}{2 \sqrt {a} \sqrt {d} \sqrt {e} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}\right )}{16 a^{9/2} d^{11/2} e^{9/2}}\\ \end {align*}

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Mathematica [A]  time = 1.39, size = 593, normalized size = 0.89 \begin {gather*} \frac {(a e+c d x) \left (24 a^{7/2} d^{9/2} e^{7/2} \left (a e^2-c d^2\right )^3+x \left (6 a^{5/2} d^{7/2} e^{5/2} \left (c d^2-a e^2\right )^3 \left (9 a e^2+7 c d^2\right )+3 a^{3/2} d^{5/2} e^{3/2} x \left (a e^2-c d^2\right )^3 \left (63 a^2 e^4+54 a c d^2 e^2+35 c^2 d^4\right )+x^2 \left (9 \sqrt {a} c d^{7/2} \sqrt {e} \left (c d^2-a e^2\right )^2 \left (21 a^3 e^6+3 a^2 c d^2 e^4-5 a c^2 d^4 e^2-35 c^3 d^6\right )+3 \sqrt {a} d^{3/2} \sqrt {e} \left (a e^2-c d^2\right ) \left (105 a^4 e^9-84 a^3 c d^2 e^7-42 a^2 c^2 d^4 e^5-20 a c^3 d^6 e^3+105 c^4 d^8 e\right ) (a e+c d x)+(d+e x) \sqrt {a e+c d x} \left (45 \sqrt {d+e x} \left (21 a^3 e^6+21 a^2 c d^2 e^4+15 a c^2 d^4 e^2+7 c^3 d^6\right ) \left (c d^2-a e^2\right )^3 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a e+c d x}}{\sqrt {a} \sqrt {e} \sqrt {d+e x}}\right )+3 \sqrt {a} \sqrt {d} \sqrt {e} \left (315 a^5 e^{11}-525 a^4 c d^2 e^9+78 a^3 c^2 d^4 e^7+54 a^2 c^3 d^6 e^5+55 a c^4 d^8 e^3-105 c^5 d^{10} e\right ) \sqrt {a e+c d x}\right )\right )\right )\right )}{72 a^{9/2} d^{11/2} e^{9/2} x^3 \left (c d^2-a e^2\right )^3 ((d+e x) (a e+c d x))^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x^4*(d + e*x)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)),x]

[Out]

((a*e + c*d*x)*(24*a^(7/2)*d^(9/2)*e^(7/2)*(-(c*d^2) + a*e^2)^3 + x*(6*a^(5/2)*d^(7/2)*e^(5/2)*(c*d^2 - a*e^2)
^3*(7*c*d^2 + 9*a*e^2) + 3*a^(3/2)*d^(5/2)*e^(3/2)*(-(c*d^2) + a*e^2)^3*(35*c^2*d^4 + 54*a*c*d^2*e^2 + 63*a^2*
e^4)*x + x^2*(9*Sqrt[a]*c*d^(7/2)*Sqrt[e]*(c*d^2 - a*e^2)^2*(-35*c^3*d^6 - 5*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 +
21*a^3*e^6) + 3*Sqrt[a]*d^(3/2)*Sqrt[e]*(-(c*d^2) + a*e^2)*(105*c^4*d^8*e - 20*a*c^3*d^6*e^3 - 42*a^2*c^2*d^4
*e^5 - 84*a^3*c*d^2*e^7 + 105*a^4*e^9)*(a*e + c*d*x) + Sqrt[a*e + c*d*x]*(d + e*x)*(3*Sqrt[a]*Sqrt[d]*Sqrt[e]*
(-105*c^5*d^10*e + 55*a*c^4*d^8*e^3 + 54*a^2*c^3*d^6*e^5 + 78*a^3*c^2*d^4*e^7 - 525*a^4*c*d^2*e^9 + 315*a^5*e^
11)*Sqrt[a*e + c*d*x] + 45*(c*d^2 - a*e^2)^3*(7*c^3*d^6 + 15*a*c^2*d^4*e^2 + 21*a^2*c*d^2*e^4 + 21*a^3*e^6)*Sq
rt[d + e*x]*ArcTanh[(Sqrt[d]*Sqrt[a*e + c*d*x])/(Sqrt[a]*Sqrt[e]*Sqrt[d + e*x])])))))/(72*a^(9/2)*d^(11/2)*e^(
9/2)*(c*d^2 - a*e^2)^3*x^3*((a*e + c*d*x)*(d + e*x))^(3/2))

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IntegrateAlgebraic [A]  time = 9.13, size = 711, normalized size = 1.07 \begin {gather*} \frac {\sqrt {a d e+a e^2 x+c d^2 x+c d e x^2} \left (-8 a^6 d^4 e^9+18 a^6 d^3 e^{10} x-63 a^6 d^2 e^{11} x^2-420 a^6 d e^{12} x^3-315 a^6 e^{13} x^4+24 a^5 c d^6 e^7-40 a^5 c d^5 e^8 x+135 a^5 c d^4 e^9 x^2+651 a^5 c d^3 e^{10} x^3+105 a^5 c d^2 e^{11} x^4-315 a^5 c d e^{12} x^5-24 a^4 c^2 d^8 e^5+12 a^4 c^2 d^7 e^6 x-62 a^4 c^2 d^6 e^7 x^2-3 a^4 c^2 d^5 e^8 x^3+636 a^4 c^2 d^4 e^9 x^4+525 a^4 c^2 d^3 e^{10} x^5+8 a^3 c^3 d^{10} e^3+24 a^3 c^3 d^9 e^4 x+6 a^3 c^3 d^8 e^5 x^2-106 a^3 c^3 d^7 e^6 x^3-174 a^3 c^3 d^6 e^7 x^4-78 a^3 c^3 d^5 e^8 x^5-14 a^2 c^4 d^{11} e^2 x-51 a^2 c^4 d^{10} e^3 x^2-114 a^2 c^4 d^9 e^4 x^3-131 a^2 c^4 d^8 e^5 x^4-54 a^2 c^4 d^7 e^6 x^5+35 a c^5 d^{12} e x^2+15 a c^5 d^{11} e^2 x^3-75 a c^5 d^{10} e^3 x^4-55 a c^5 d^9 e^4 x^5+105 c^6 d^{13} x^3+210 c^6 d^{12} e x^4+105 c^6 d^{11} e^2 x^5\right )}{24 a^4 d^5 e^4 x^3 (d+e x)^2 \left (a e^2-c d^2\right )^3 (a e+c d x)}-\frac {5 \left (21 a^3 e^6+21 a^2 c d^2 e^4+15 a c^2 d^4 e^2+7 c^3 d^6\right ) \tanh ^{-1}\left (\frac {x \sqrt {c d e}-\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{\sqrt {a} \sqrt {d} \sqrt {e}}\right )}{8 a^{9/2} d^{11/2} e^{9/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/(x^4*(d + e*x)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)),x]

[Out]

(Sqrt[a*d*e + c*d^2*x + a*e^2*x + c*d*e*x^2]*(8*a^3*c^3*d^10*e^3 - 24*a^4*c^2*d^8*e^5 + 24*a^5*c*d^6*e^7 - 8*a
^6*d^4*e^9 - 14*a^2*c^4*d^11*e^2*x + 24*a^3*c^3*d^9*e^4*x + 12*a^4*c^2*d^7*e^6*x - 40*a^5*c*d^5*e^8*x + 18*a^6
*d^3*e^10*x + 35*a*c^5*d^12*e*x^2 - 51*a^2*c^4*d^10*e^3*x^2 + 6*a^3*c^3*d^8*e^5*x^2 - 62*a^4*c^2*d^6*e^7*x^2 +
135*a^5*c*d^4*e^9*x^2 - 63*a^6*d^2*e^11*x^2 + 105*c^6*d^13*x^3 + 15*a*c^5*d^11*e^2*x^3 - 114*a^2*c^4*d^9*e^4*
x^3 - 106*a^3*c^3*d^7*e^6*x^3 - 3*a^4*c^2*d^5*e^8*x^3 + 651*a^5*c*d^3*e^10*x^3 - 420*a^6*d*e^12*x^3 + 210*c^6*
d^12*e*x^4 - 75*a*c^5*d^10*e^3*x^4 - 131*a^2*c^4*d^8*e^5*x^4 - 174*a^3*c^3*d^6*e^7*x^4 + 636*a^4*c^2*d^4*e^9*x
^4 + 105*a^5*c*d^2*e^11*x^4 - 315*a^6*e^13*x^4 + 105*c^6*d^11*e^2*x^5 - 55*a*c^5*d^9*e^4*x^5 - 54*a^2*c^4*d^7*
e^6*x^5 - 78*a^3*c^3*d^5*e^8*x^5 + 525*a^4*c^2*d^3*e^10*x^5 - 315*a^5*c*d*e^12*x^5))/(24*a^4*d^5*e^4*(-(c*d^2)
+ a*e^2)^3*x^3*(a*e + c*d*x)*(d + e*x)^2) - (5*(7*c^3*d^6 + 15*a*c^2*d^4*e^2 + 21*a^2*c*d^2*e^4 + 21*a^3*e^6)
*ArcTanh[(Sqrt[c*d*e]*x - Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2])/(Sqrt[a]*Sqrt[d]*Sqrt[e])])/(8*a^(9/2)*
d^(11/2)*e^(9/2))

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fricas [B]  time = 93.16, size = 2526, normalized size = 3.80

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(e*x+d)/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2),x, algorithm="fricas")

[Out]

[1/96*(15*((7*c^7*d^13*e^2 - 6*a*c^6*d^11*e^4 - 3*a^2*c^5*d^9*e^6 - 4*a^3*c^4*d^7*e^8 - 15*a^4*c^3*d^5*e^10 +
42*a^5*c^2*d^3*e^12 - 21*a^6*c*d*e^14)*x^6 + (14*c^7*d^14*e - 5*a*c^6*d^12*e^3 - 12*a^2*c^5*d^10*e^5 - 11*a^3*
c^4*d^8*e^7 - 34*a^4*c^3*d^6*e^9 + 69*a^5*c^2*d^4*e^11 - 21*a^7*e^15)*x^5 + (7*c^7*d^15 + 8*a*c^6*d^13*e^2 - 1
5*a^2*c^5*d^11*e^4 - 10*a^3*c^4*d^9*e^6 - 23*a^4*c^3*d^7*e^8 + 12*a^5*c^2*d^5*e^10 + 63*a^6*c*d^3*e^12 - 42*a^
7*d*e^14)*x^4 + (7*a*c^6*d^14*e - 6*a^2*c^5*d^12*e^3 - 3*a^3*c^4*d^10*e^5 - 4*a^4*c^3*d^8*e^7 - 15*a^5*c^2*d^6
*e^9 + 42*a^6*c*d^4*e^11 - 21*a^7*d^2*e^13)*x^3)*sqrt(a*d*e)*log((8*a^2*d^2*e^2 + (c^2*d^4 + 6*a*c*d^2*e^2 + a
^2*e^4)*x^2 + 4*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*(2*a*d*e + (c*d^2 + a*e^2)*x)*sqrt(a*d*e) + 8*(a*c
*d^3*e + a^2*d*e^3)*x)/x^2) - 4*(8*a^4*c^3*d^11*e^4 - 24*a^5*c^2*d^9*e^6 + 24*a^6*c*d^7*e^8 - 8*a^7*d^5*e^10 +
(105*a*c^6*d^12*e^3 - 55*a^2*c^5*d^10*e^5 - 54*a^3*c^4*d^8*e^7 - 78*a^4*c^3*d^6*e^9 + 525*a^5*c^2*d^4*e^11 -
315*a^6*c*d^2*e^13)*x^5 + (210*a*c^6*d^13*e^2 - 75*a^2*c^5*d^11*e^4 - 131*a^3*c^4*d^9*e^6 - 174*a^4*c^3*d^7*e^
8 + 636*a^5*c^2*d^5*e^10 + 105*a^6*c*d^3*e^12 - 315*a^7*d*e^14)*x^4 + (105*a*c^6*d^14*e + 15*a^2*c^5*d^12*e^3
- 114*a^3*c^4*d^10*e^5 - 106*a^4*c^3*d^8*e^7 - 3*a^5*c^2*d^6*e^9 + 651*a^6*c*d^4*e^11 - 420*a^7*d^2*e^13)*x^3
+ (35*a^2*c^5*d^13*e^2 - 51*a^3*c^4*d^11*e^4 + 6*a^4*c^3*d^9*e^6 - 62*a^5*c^2*d^7*e^8 + 135*a^6*c*d^5*e^10 - 6
3*a^7*d^3*e^12)*x^2 - 2*(7*a^3*c^4*d^12*e^3 - 12*a^4*c^3*d^10*e^5 - 6*a^5*c^2*d^8*e^7 + 20*a^6*c*d^6*e^9 - 9*a
^7*d^4*e^11)*x)*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x))/((a^5*c^4*d^13*e^7 - 3*a^6*c^3*d^11*e^9 + 3*a^7*c
^2*d^9*e^11 - a^8*c*d^7*e^13)*x^6 + (2*a^5*c^4*d^14*e^6 - 5*a^6*c^3*d^12*e^8 + 3*a^7*c^2*d^10*e^10 + a^8*c*d^8
*e^12 - a^9*d^6*e^14)*x^5 + (a^5*c^4*d^15*e^5 - a^6*c^3*d^13*e^7 - 3*a^7*c^2*d^11*e^9 + 5*a^8*c*d^9*e^11 - 2*a
^9*d^7*e^13)*x^4 + (a^6*c^3*d^14*e^6 - 3*a^7*c^2*d^12*e^8 + 3*a^8*c*d^10*e^10 - a^9*d^8*e^12)*x^3), -1/48*(15*
((7*c^7*d^13*e^2 - 6*a*c^6*d^11*e^4 - 3*a^2*c^5*d^9*e^6 - 4*a^3*c^4*d^7*e^8 - 15*a^4*c^3*d^5*e^10 + 42*a^5*c^2
*d^3*e^12 - 21*a^6*c*d*e^14)*x^6 + (14*c^7*d^14*e - 5*a*c^6*d^12*e^3 - 12*a^2*c^5*d^10*e^5 - 11*a^3*c^4*d^8*e^
7 - 34*a^4*c^3*d^6*e^9 + 69*a^5*c^2*d^4*e^11 - 21*a^7*e^15)*x^5 + (7*c^7*d^15 + 8*a*c^6*d^13*e^2 - 15*a^2*c^5*
d^11*e^4 - 10*a^3*c^4*d^9*e^6 - 23*a^4*c^3*d^7*e^8 + 12*a^5*c^2*d^5*e^10 + 63*a^6*c*d^3*e^12 - 42*a^7*d*e^14)*
x^4 + (7*a*c^6*d^14*e - 6*a^2*c^5*d^12*e^3 - 3*a^3*c^4*d^10*e^5 - 4*a^4*c^3*d^8*e^7 - 15*a^5*c^2*d^6*e^9 + 42*
a^6*c*d^4*e^11 - 21*a^7*d^2*e^13)*x^3)*sqrt(-a*d*e)*arctan(1/2*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*(2*
a*d*e + (c*d^2 + a*e^2)*x)*sqrt(-a*d*e)/(a*c*d^2*e^2*x^2 + a^2*d^2*e^2 + (a*c*d^3*e + a^2*d*e^3)*x)) + 2*(8*a^
4*c^3*d^11*e^4 - 24*a^5*c^2*d^9*e^6 + 24*a^6*c*d^7*e^8 - 8*a^7*d^5*e^10 + (105*a*c^6*d^12*e^3 - 55*a^2*c^5*d^1
0*e^5 - 54*a^3*c^4*d^8*e^7 - 78*a^4*c^3*d^6*e^9 + 525*a^5*c^2*d^4*e^11 - 315*a^6*c*d^2*e^13)*x^5 + (210*a*c^6*
d^13*e^2 - 75*a^2*c^5*d^11*e^4 - 131*a^3*c^4*d^9*e^6 - 174*a^4*c^3*d^7*e^8 + 636*a^5*c^2*d^5*e^10 + 105*a^6*c*
d^3*e^12 - 315*a^7*d*e^14)*x^4 + (105*a*c^6*d^14*e + 15*a^2*c^5*d^12*e^3 - 114*a^3*c^4*d^10*e^5 - 106*a^4*c^3*
d^8*e^7 - 3*a^5*c^2*d^6*e^9 + 651*a^6*c*d^4*e^11 - 420*a^7*d^2*e^13)*x^3 + (35*a^2*c^5*d^13*e^2 - 51*a^3*c^4*d
^11*e^4 + 6*a^4*c^3*d^9*e^6 - 62*a^5*c^2*d^7*e^8 + 135*a^6*c*d^5*e^10 - 63*a^7*d^3*e^12)*x^2 - 2*(7*a^3*c^4*d^
12*e^3 - 12*a^4*c^3*d^10*e^5 - 6*a^5*c^2*d^8*e^7 + 20*a^6*c*d^6*e^9 - 9*a^7*d^4*e^11)*x)*sqrt(c*d*e*x^2 + a*d*
e + (c*d^2 + a*e^2)*x))/((a^5*c^4*d^13*e^7 - 3*a^6*c^3*d^11*e^9 + 3*a^7*c^2*d^9*e^11 - a^8*c*d^7*e^13)*x^6 + (
2*a^5*c^4*d^14*e^6 - 5*a^6*c^3*d^12*e^8 + 3*a^7*c^2*d^10*e^10 + a^8*c*d^8*e^12 - a^9*d^6*e^14)*x^5 + (a^5*c^4*
d^15*e^5 - a^6*c^3*d^13*e^7 - 3*a^7*c^2*d^11*e^9 + 5*a^8*c*d^9*e^11 - 2*a^9*d^7*e^13)*x^4 + (a^6*c^3*d^14*e^6
- 3*a^7*c^2*d^12*e^8 + 3*a^8*c*d^10*e^10 - a^9*d^8*e^12)*x^3)]

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(e*x+d)/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:Eval
uation time: 0.42Unable to transpose Error: Bad Argument Value

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maple [B]  time = 0.02, size = 1705, normalized size = 2.57

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^4/(e*x+d)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(3/2),x)

[Out]

35/8*d^4/a^4/e^3/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*x*c^5+25/12/e*d^2/a^
3/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*x*c^4-41/12/d^2*e^3/a/(-a^2*e^4+2*a
*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*x*c^2+75/16/e^2/d/a^3/(a*d*e)^(1/2)*ln((2*a*d*e+(a
*e^2+c*d^2)*x+2*(a*d*e)^(1/2)*(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2))/x)*c^2-1/6*e/a^2/(-a^2*e^4+2*a*c*d^2*e^
2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*x*c^3-43/24/d*e^2/a/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e
*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*c^2+105/8/d^4*e^5/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c
*d^2)*x)^(1/2)*x*c+35/16*d^5/a^4/e^4/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*
c^5+35/16*d/a^4/e^4/(a*d*e)^(1/2)*ln((2*a*d*e+(a*e^2+c*d^2)*x+2*(a*d*e)^(1/2)*(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x
)^(1/2))/x)*c^3+16/3/d^2*e^5*c^2/(a*e^2-c*d^2)^3/((x+d/e)^2*c*d*e+(a*e^2-c*d^2)*(x+d/e))^(1/2)*x+8/3/d^3*e^6*c
/(a*e^2-c*d^2)^3/((x+d/e)^2*c*d*e+(a*e^2-c*d^2)*(x+d/e))^(1/2)*a-17/6/e/d^2/a^2/x/(c*d*e*x^2+a*d*e+(a*e^2+c*d^
2)*x)^(1/2)*c+155/48/e^2*d^3/a^3/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*c^4+
7/12/d/a^2/e^2/x^2/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*c+13/12/d^3/a/x^2/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)
^(1/2)-105/16/d^5*e^2/a/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)-105/16/d^3/a^2/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*
x)^(1/2)*c-89/24/d^4*e/a/x/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)+105/16/d^5*e^6*a/(-a^2*e^4+2*a*c*d^2*e^2-c^
2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)+233/48/d^3*e^4/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*
e+(a*e^2+c*d^2)*x)^(1/2)*c+23/24*d/a^2/(-a^2*e^4+2*a*c*d^2*e^2-c^2*d^4)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2
)*c^3+105/16/d^5*e^2/a/(a*d*e)^(1/2)*ln((2*a*d*e+(a*e^2+c*d^2)*x+2*(a*d*e)^(1/2)*(c*d*e*x^2+a*d*e+(a*e^2+c*d^2
)*x)^(1/2))/x)+105/16/d^3/a^2/(a*d*e)^(1/2)*ln((2*a*d*e+(a*e^2+c*d^2)*x+2*(a*d*e)^(1/2)*(c*d*e*x^2+a*d*e+(a*e^
2+c*d^2)*x)^(1/2))/x)*c-75/16/e^2/d/a^3/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*c^2-35/24/a^3/e^3/x/(c*d*e*x^2
+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*c^2-1/3/d^2/a/e/x^3/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)-35/16*d/a^4/e^4/(c*d
*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(1/2)*c^3-2/3/d^4*e^3/(a*e^2-c*d^2)/(x+d/e)/((x+d/e)^2*c*d*e+(a*e^2-c*d^2)*(x+d/
e))^(1/2)+8/3/d*e^4*c^2/(a*e^2-c*d^2)^3/((x+d/e)^2*c*d*e+(a*e^2-c*d^2)*(x+d/e))^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{{\left (c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x\right )}^{\frac {3}{2}} {\left (e x + d\right )} x^{4}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(e*x+d)/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2),x, algorithm="maxima")

[Out]

integrate(1/((c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)^(3/2)*(e*x + d)*x^4), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{x^4\,\left (d+e\,x\right )\,{\left (c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e\right )}^{3/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^4*(d + e*x)*(x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(3/2)),x)

[Out]

int(1/(x^4*(d + e*x)*(x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(3/2)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x^{4} \left (\left (d + e x\right ) \left (a e + c d x\right )\right )^{\frac {3}{2}} \left (d + e x\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**4/(e*x+d)/(a*d*e+(a*e**2+c*d**2)*x+c*d*e*x**2)**(3/2),x)

[Out]

Integral(1/(x**4*((d + e*x)*(a*e + c*d*x))**(3/2)*(d + e*x)), x)

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